构建基于图数据库的问答应用程序
在本指南中,我们将介绍在图数据库上创建问答链的基本方法。这些系统将使我们能够针对图数据库中的数据提出问题并获得自然语言答案。首先,我们将展示一个简单的开箱即用选项,然后使用 LangGraph 实现一个更复杂的版本。
⚠️ 安全注意事项 ⚠️
构建图数据库问答系统需要执行模型生成的图查询。这样做存在固有风险。请确保您的数据库连接权限始终尽可能地限制在链/代理所需范围内。这将减轻但不能消除构建模型驱动系统的风险。有关一般安全最佳实践的更多信息,请参阅此处。
架构
从高层次来看,大多数图链的步骤是:
- 将问题转换为图数据库查询:模型将用户输入转换为图数据库查询(例如 Cypher)。
- 执行图数据库查询:执行图数据库查询。
- 回答问题:模型使用查询结果响应用户输入。
设置
首先,获取所需软件包并设置环境变量。在此示例中,我们将使用 Neo4j 图数据库。
%pip install --upgrade --quiet langchain langchain-neo4j langchain-openai langgraph
本指南中我们默认使用 OpenAI 模型。
import getpass
import os
if "OPENAI_API_KEY" not in os.environ:
os.environ["OPENAI_API_KEY"] = getpass.getpass("Enter your OpenAI API key: ")
# Uncomment the below to use LangSmith. Not required.
# os.environ["LANGSMITH_API_KEY"] = getpass.getpass()
# os.environ["LANGSMITH_TRACING"] = "true"
Enter your OpenAI API key: ········
接下来,我们需要定义 Neo4j 凭据。按照这些安装步骤设置 Neo4j 数据库。
os.environ["NEO4J_URI"] = "bolt://:7687"
os.environ["NEO4J_USERNAME"] = "neo4j"
os.environ["NEO4J_PASSWORD"] = "password"
以下示例将与 Neo4j 数据库建立连接,并用有关电影及其演员的示例数据填充它。
from langchain_neo4j import Neo4jGraph
graph = Neo4jGraph()
# Import movie information
movies_query = """
LOAD CSV WITH HEADERS FROM
'https://raw.githubusercontent.com/tomasonjo/blog-datasets/main/movies/movies_small.csv'
AS row
MERGE (m:Movie {id:row.movieId})
SET m.released = date(row.released),
m.title = row.title,
m.imdbRating = toFloat(row.imdbRating)
FOREACH (director in split(row.director, '|') |
MERGE (p:Person {name:trim(director)})
MERGE (p)-[:DIRECTED]->(m))
FOREACH (actor in split(row.actors, '|') |
MERGE (p:Person {name:trim(actor)})
MERGE (p)-[:ACTED_IN]->(m))
FOREACH (genre in split(row.genres, '|') |
MERGE (g:Genre {name:trim(genre)})
MERGE (m)-[:IN_GENRE]->(g))
"""
graph.query(movies_query)
[]
图模式
为了让大型语言模型(LLM)能够生成 Cypher 语句,它需要图模式信息。当您实例化图对象时,它会检索图模式信息。如果您稍后对图进行了任何更改,可以运行 refresh_schema
方法来刷新模式信息。
graph.refresh_schema()
print(graph.schema)
Node properties:
Person {name: STRING}
Movie {id: STRING, released: DATE, title: STRING, imdbRating: FLOAT}
Genre {name: STRING}
Chunk {id: STRING, embedding: LIST, text: STRING, question: STRING, query: STRING}
Relationship properties:
The relationships:
(:Person)-[:DIRECTED]->(:Movie)
(:Person)-[:ACTED_IN]->(:Movie)
(:Movie)-[:IN_GENRE]->(:Genre)
对于更复杂的模式信息,您可以使用 enhanced_schema
选项。
enhanced_graph = Neo4jGraph(enhanced_schema=True)
print(enhanced_graph.schema)
Received notification from DBMS server: {severity: WARNING} {code: Neo.ClientNotification.Statement.FeatureDeprecationWarning} {category: DEPRECATION} {title: This feature is deprecated and will be removed in future versions.} {description: The procedure has a deprecated field. ('config' used by 'apoc.meta.graphSample' is deprecated.)} {position: line: 1, column: 1, offset: 0} for query: "CALL apoc.meta.graphSample() YIELD nodes, relationships RETURN nodes, [rel in relationships | {name:apoc.any.property(rel, 'type'), count: apoc.any.property(rel, 'count')}] AS relationships"
``````output
Node properties:
- **Person**
- `name`: STRING Example: "John Lasseter"
- **Movie**
- `id`: STRING Example: "1"
- `released`: DATE Min: 1964-12-16, Max: 1996-09-15
- `title`: STRING Example: "Toy Story"
- `imdbRating`: FLOAT Min: 2.4, Max: 9.3
- **Genre**
- `name`: STRING Example: "Adventure"
- **Chunk**
- `id`: STRING Available options: ['d66006059fd78d63f3df90cc1059639a', '0e3dcb4502853979d12357690a95ec17', 'c438c6bcdcf8e4fab227f29f8e7ff204', '97fe701ec38057594464beaa2df0710e', 'b54f9286e684373498c4504b4edd9910', '5b50a72c3a4954b0ff7a0421be4f99b9', 'fb28d41771e717255f0d8f6c799ede32', '58e6f14dd2e6c6702cf333f2335c499c']
- `text`: STRING Available options: ['How many artists are there?', 'Which actors played in the movie Casino?', 'How many movies has Tom Hanks acted in?', "List all the genres of the movie Schindler's List", 'Which actors have worked in movies from both the c', 'Which directors have made movies with at least thr', 'Identify movies where directors also played a role', 'Find the actor with the highest number of movies i']
- `question`: STRING Available options: ['How many artists are there?', 'Which actors played in the movie Casino?', 'How many movies has Tom Hanks acted in?', "List all the genres of the movie Schindler's List", 'Which actors have worked in movies from both the c', 'Which directors have made movies with at least thr', 'Identify movies where directors also played a role', 'Find the actor with the highest number of movies i']
- `query`: STRING Available options: ['MATCH (a:Person)-[:ACTED_IN]->(:Movie) RETURN coun', "MATCH (m:Movie {title: 'Casino'})<-[:ACTED_IN]-(a)", "MATCH (a:Person {name: 'Tom Hanks'})-[:ACTED_IN]->", "MATCH (m:Movie {title: 'Schindler's List'})-[:IN_G", 'MATCH (a:Person)-[:ACTED_IN]->(:Movie)-[:IN_GENRE]', 'MATCH (d:Person)-[:DIRECTED]->(m:Movie)<-[:ACTED_I', 'MATCH (p:Person)-[:DIRECTED]->(m:Movie), (p)-[:ACT', 'MATCH (a:Actor)-[:ACTED_IN]->(m:Movie) RETURN a.na']
Relationship properties:
The relationships:
(:Person)-[:DIRECTED]->(:Movie)
(:Person)-[:ACTED_IN]->(:Movie)
(:Movie)-[:IN_GENRE]->(:Genre)
enhanced_schema
选项通过包含浮点数和日期的最小值和最大值,以及字符串属性的示例值等详细信息,丰富了属性信息。这种额外的上下文有助于引导 LLM 生成更准确和有效的查询。
太棒了!我们已经有了一个可以查询的图数据库。现在让我们尝试将其连接到 LLM。
GraphQACypherChain
让我们使用一个简单的开箱即用链,它接收一个问题,将其转换为 Cypher 查询,执行查询,并使用结果回答原始问题。
LangChain 提供了一个内置链,用于此工作流,专门为 Neo4j 设计:GraphCypherQAChain
from langchain_neo4j import GraphCypherQAChain
from langchain_openai import ChatOpenAI
llm = ChatOpenAI(model="gpt-4o", temperature=0)
chain = GraphCypherQAChain.from_llm(
graph=enhanced_graph, llm=llm, verbose=True, allow_dangerous_requests=True
)
response = chain.invoke({"query": "What was the cast of the Casino?"})
response
[1m> Entering new GraphCypherQAChain chain...[0m
Generated Cypher:
[32;1m[1;3mcypher
MATCH (p:Person)-[:ACTED_IN]->(m:Movie {title: "Casino"})
RETURN p.name
[0m
Full Context:
[32;1m[1;3m[{'p.name': 'Robert De Niro'}, {'p.name': 'Joe Pesci'}, {'p.name': 'Sharon Stone'}, {'p.name': 'James Woods'}][0m
[1m> Finished chain.[0m
{'query': 'What was the cast of the Casino?',
'result': 'Robert De Niro, Joe Pesci, Sharon Stone, and James Woods were the cast of Casino.'}
使用 LangGraph 进行高级实现
虽然 GraphCypherQAChain 对于快速演示是有效的,但在生产环境中可能会面临挑战。过渡到 LangGraph 可以增强工作流,但在生产中实现自然语言到查询的流程仍然是一项复杂的任务。尽管如此,仍有几种策略可以显著提高准确性和可靠性,我们将在接下来进行探讨。
这是我们将要实现的 LangGraph 可视化流程:
我们将从定义 LangGraph 应用程序的输入、输出和总体状态开始。
from operator import add
from typing import Annotated, List
from typing_extensions import TypedDict
class InputState(TypedDict):
question: str
class OverallState(TypedDict):
question: str
next_action: str
cypher_statement: str
cypher_errors: List[str]
database_records: List[dict]
steps: Annotated[List[str], add]
class OutputState(TypedDict):
answer: str
steps: List[str]
cypher_statement: str
第一步是一个简单的 guardrails
步骤,我们在此验证问题是否与电影或其演员有关。如果不相关,我们会通知用户我们无法回答任何其他问题。否则,我们将进入 Cypher 生成步骤。
from typing import Literal
from langchain_core.prompts import ChatPromptTemplate
from pydantic import BaseModel, Field
guardrails_system = """
As an intelligent assistant, your primary objective is to decide whether a given question is related to movies or not.
If the question is related to movies, output "movie". Otherwise, output "end".
To make this decision, assess the content of the question and determine if it refers to any movie, actor, director, film industry,
or related topics. Provide only the specified output: "movie" or "end".
"""
guardrails_prompt = ChatPromptTemplate.from_messages(
[
(
"system",
guardrails_system,
),
(
"human",
("{question}"),
),
]
)
class GuardrailsOutput(BaseModel):
decision: Literal["movie", "end"] = Field(
description="Decision on whether the question is related to movies"
)
guardrails_chain = guardrails_prompt | llm.with_structured_output(GuardrailsOutput)
def guardrails(state: InputState) -> OverallState:
"""
Decides if the question is related to movies or not.
"""
guardrails_output = guardrails_chain.invoke({"question": state.get("question")})
database_records = None
if guardrails_output.decision == "end":
database_records = "This questions is not about movies or their cast. Therefore I cannot answer this question."
return {
"next_action": guardrails_output.decision,
"database_records": database_records,
"steps": ["guardrail"],
}
少样本提示
将自然语言转换为准确的查询是一项挑战。一种增强此过程的方法是提供相关的少样本示例,以指导大型语言模型(LLM)进行查询生成。为了实现这一点,我们将使用 SemanticSimilarityExampleSelector
动态选择最相关的示例。
from langchain_core.example_selectors import SemanticSimilarityExampleSelector
from langchain_neo4j import Neo4jVector
from langchain_openai import OpenAIEmbeddings
examples = [
{
"question": "How many artists are there?",
"query": "MATCH (a:Person)-[:ACTED_IN]->(:Movie) RETURN count(DISTINCT a)",
},
{
"question": "Which actors played in the movie Casino?",
"query": "MATCH (m:Movie {title: 'Casino'})<-[:ACTED_IN]-(a) RETURN a.name",
},
{
"question": "How many movies has Tom Hanks acted in?",
"query": "MATCH (a:Person {name: 'Tom Hanks'})-[:ACTED_IN]->(m:Movie) RETURN count(m)",
},
{
"question": "List all the genres of the movie Schindler's List",
"query": "MATCH (m:Movie {title: 'Schindler's List'})-[:IN_GENRE]->(g:Genre) RETURN g.name",
},
{
"question": "Which actors have worked in movies from both the comedy and action genres?",
"query": "MATCH (a:Person)-[:ACTED_IN]->(:Movie)-[:IN_GENRE]->(g1:Genre), (a)-[:ACTED_IN]->(:Movie)-[:IN_GENRE]->(g2:Genre) WHERE g1.name = 'Comedy' AND g2.name = 'Action' RETURN DISTINCT a.name",
},
{
"question": "Which directors have made movies with at least three different actors named 'John'?",
"query": "MATCH (d:Person)-[:DIRECTED]->(m:Movie)<-[:ACTED_IN]-(a:Person) WHERE a.name STARTS WITH 'John' WITH d, COUNT(DISTINCT a) AS JohnsCount WHERE JohnsCount >= 3 RETURN d.name",
},
{
"question": "Identify movies where directors also played a role in the film.",
"query": "MATCH (p:Person)-[:DIRECTED]->(m:Movie), (p)-[:ACTED_IN]->(m) RETURN m.title, p.name",
},
{
"question": "Find the actor with the highest number of movies in the database.",
"query": "MATCH (a:Actor)-[:ACTED_IN]->(m:Movie) RETURN a.name, COUNT(m) AS movieCount ORDER BY movieCount DESC LIMIT 1",
},
]
example_selector = SemanticSimilarityExampleSelector.from_examples(
examples, OpenAIEmbeddings(), Neo4jVector, k=5, input_keys=["question"]
)
接下来,我们实现 Cypher 生成链,也称为 text2cypher。提示包含增强的图模式、动态选择的少样本示例以及用户的提问。这种组合能够生成 Cypher 查询,从数据库中检索相关信息。
from langchain_core.output_parsers import StrOutputParser
text2cypher_prompt = ChatPromptTemplate.from_messages(
[
(
"system",
(
"Given an input question, convert it to a Cypher query. No pre-amble."
"Do not wrap the response in any backticks or anything else. Respond with a Cypher statement only!"
),
),
(
"human",
(
"""You are a Neo4j expert. Given an input question, create a syntactically correct Cypher query to run.
Do not wrap the response in any backticks or anything else. Respond with a Cypher statement only!
Here is the schema information
{schema}
Below are a number of examples of questions and their corresponding Cypher queries.
{fewshot_examples}
User input: {question}
Cypher query:"""
),
),
]
)
text2cypher_chain = text2cypher_prompt | llm | StrOutputParser()
def generate_cypher(state: OverallState) -> OverallState:
"""
Generates a cypher statement based on the provided schema and user input
"""
NL = "\n"
fewshot_examples = (NL * 2).join(
[
f"Question: {el['question']}{NL}Cypher:{el['query']}"
for el in example_selector.select_examples(
{"question": state.get("question")}
)
]
)
generated_cypher = text2cypher_chain.invoke(
{
"question": state.get("question"),
"fewshot_examples": fewshot_examples,
"schema": enhanced_graph.schema,
}
)
return {"cypher_statement": generated_cypher, "steps": ["generate_cypher"]}
查询验证
下一步是验证生成的 Cypher 语句并确保所有属性值都准确无误。虽然数字和日期通常不需要验证,但电影名称或人名等字符串确实需要。在此示例中,我们将使用基本的 CONTAINS
子句进行验证,但如果需要,可以实现更高级的映射和验证技术。
首先,我们将创建一个链,用于检测 Cypher 语句中的任何错误并提取其引用的属性值。
from typing import List, Optional
validate_cypher_system = """
You are a Cypher expert reviewing a statement written by a junior developer.
"""
validate_cypher_user = """You must check the following:
* Are there any syntax errors in the Cypher statement?
* Are there any missing or undefined variables in the Cypher statement?
* Are any node labels missing from the schema?
* Are any relationship types missing from the schema?
* Are any of the properties not included in the schema?
* Does the Cypher statement include enough information to answer the question?
Examples of good errors:
* Label (:Foo) does not exist, did you mean (:Bar)?
* Property bar does not exist for label Foo, did you mean baz?
* Relationship FOO does not exist, did you mean FOO_BAR?
Schema:
{schema}
The question is:
{question}
The Cypher statement is:
{cypher}
Make sure you don't make any mistakes!"""
validate_cypher_prompt = ChatPromptTemplate.from_messages(
[
(
"system",
validate_cypher_system,
),
(
"human",
(validate_cypher_user),
),
]
)
class Property(BaseModel):
"""
Represents a filter condition based on a specific node property in a graph in a Cypher statement.
"""
node_label: str = Field(
description="The label of the node to which this property belongs."
)
property_key: str = Field(description="The key of the property being filtered.")
property_value: str = Field(
description="The value that the property is being matched against."
)
class ValidateCypherOutput(BaseModel):
"""
Represents the validation result of a Cypher query's output,
including any errors and applied filters.
"""
errors: Optional[List[str]] = Field(
description="A list of syntax or semantical errors in the Cypher statement. Always explain the discrepancy between schema and Cypher statement"
)
filters: Optional[List[Property]] = Field(
description="A list of property-based filters applied in the Cypher statement."
)
validate_cypher_chain = validate_cypher_prompt | llm.with_structured_output(
ValidateCypherOutput
)
大型语言模型(LLM)在正确判断生成的 Cypher 语句中的关系方向时常常遇到困难。由于我们能够访问模式,因此可以使用 CypherQueryCorrector 确定性地纠正这些方向。
注意:CypherQueryCorrector
是一个实验性功能,不支持所有最新的 Cypher 语法。
from langchain_neo4j.chains.graph_qa.cypher_utils import CypherQueryCorrector, Schema
# Cypher query corrector is experimental
corrector_schema = [
Schema(el["start"], el["type"], el["end"])
for el in enhanced_graph.structured_schema.get("relationships")
]
cypher_query_corrector = CypherQueryCorrector(corrector_schema)
现在我们可以实现 Cypher 验证步骤。首先,我们使用 EXPLAIN
方法检测任何语法错误。接下来,我们利用 LLM 识别潜在问题并提取用于过滤的属性。对于字符串属性,我们使用简单的 CONTAINS
子句对其进行数据库验证。
根据验证结果,流程可以采取以下路径:
- 如果值映射失败,我们结束对话并通知用户我们无法识别特定的属性值(例如,人名或电影名称)。
- 如果发现错误,我们将查询路由进行更正。
- 如果没有检测到问题,我们继续执行 Cypher 执行步骤。
from neo4j.exceptions import CypherSyntaxError
def validate_cypher(state: OverallState) -> OverallState:
"""
Validates the Cypher statements and maps any property values to the database.
"""
errors = []
mapping_errors = []
# Check for syntax errors
try:
enhanced_graph.query(f"EXPLAIN {state.get('cypher_statement')}")
except CypherSyntaxError as e:
errors.append(e.message)
# Experimental feature for correcting relationship directions
corrected_cypher = cypher_query_corrector(state.get("cypher_statement"))
if not corrected_cypher:
errors.append("The generated Cypher statement doesn't fit the graph schema")
if not corrected_cypher == state.get("cypher_statement"):
print("Relationship direction was corrected")
# Use LLM to find additional potential errors and get the mapping for values
llm_output = validate_cypher_chain.invoke(
{
"question": state.get("question"),
"schema": enhanced_graph.schema,
"cypher": state.get("cypher_statement"),
}
)
if llm_output.errors:
errors.extend(llm_output.errors)
if llm_output.filters:
for filter in llm_output.filters:
# Do mapping only for string values
if (
not [
prop
for prop in enhanced_graph.structured_schema["node_props"][
filter.node_label
]
if prop["property"] == filter.property_key
][0]["type"]
== "STRING"
):
continue
mapping = enhanced_graph.query(
f"MATCH (n:{filter.node_label}) WHERE toLower(n.`{filter.property_key}`) = toLower($value) RETURN 'yes' LIMIT 1",
{"value": filter.property_value},
)
if not mapping:
print(
f"Missing value mapping for {filter.node_label} on property {filter.property_key} with value {filter.property_value}"
)
mapping_errors.append(
f"Missing value mapping for {filter.node_label} on property {filter.property_key} with value {filter.property_value}"
)
if mapping_errors:
next_action = "end"
elif errors:
next_action = "correct_cypher"
else:
next_action = "execute_cypher"
return {
"next_action": next_action,
"cypher_statement": corrected_cypher,
"cypher_errors": errors,
"steps": ["validate_cypher"],
}
Cypher 校正步骤会获取现有 Cypher 语句、任何已识别的错误和原始问题,以生成查询的校正版本。
correct_cypher_prompt = ChatPromptTemplate.from_messages(
[
(
"system",
(
"You are a Cypher expert reviewing a statement written by a junior developer. "
"You need to correct the Cypher statement based on the provided errors. No pre-amble."
"Do not wrap the response in any backticks or anything else. Respond with a Cypher statement only!"
),
),
(
"human",
(
"""Check for invalid syntax or semantics and return a corrected Cypher statement.
Schema:
{schema}
Note: Do not include any explanations or apologies in your responses.
Do not wrap the response in any backticks or anything else.
Respond with a Cypher statement only!
Do not respond to any questions that might ask anything else than for you to construct a Cypher statement.
The question is:
{question}
The Cypher statement is:
{cypher}
The errors are:
{errors}
Corrected Cypher statement: """
),
),
]
)
correct_cypher_chain = correct_cypher_prompt | llm | StrOutputParser()
def correct_cypher(state: OverallState) -> OverallState:
"""
Correct the Cypher statement based on the provided errors.
"""
corrected_cypher = correct_cypher_chain.invoke(
{
"question": state.get("question"),
"errors": state.get("cypher_errors"),
"cypher": state.get("cypher_statement"),
"schema": enhanced_graph.schema,
}
)
return {
"next_action": "validate_cypher",
"cypher_statement": corrected_cypher,
"steps": ["correct_cypher"],
}
我们需要添加一个执行给定 Cypher 语句的步骤。如果没有返回结果,我们应该明确处理这种情况,因为上下文为空有时可能导致 LLM 幻觉。
no_results = "I couldn't find any relevant information in the database"
def execute_cypher(state: OverallState) -> OverallState:
"""
Executes the given Cypher statement.
"""
records = enhanced_graph.query(state.get("cypher_statement"))
return {
"database_records": records if records else no_results,
"next_action": "end",
"steps": ["execute_cypher"],
}
最后一步是生成答案。这包括将初始问题与数据库输出结合起来,生成相关的响应。
generate_final_prompt = ChatPromptTemplate.from_messages(
[
(
"system",
"You are a helpful assistant",
),
(
"human",
(
"""Use the following results retrieved from a database to provide
a succinct, definitive answer to the user's question.
Respond as if you are answering the question directly.
Results: {results}
Question: {question}"""
),
),
]
)
generate_final_chain = generate_final_prompt | llm | StrOutputParser()
def generate_final_answer(state: OverallState) -> OutputState:
"""
Decides if the question is related to movies.
"""
final_answer = generate_final_chain.invoke(
{"question": state.get("question"), "results": state.get("database_records")}
)
return {"answer": final_answer, "steps": ["generate_final_answer"]}
接下来,我们将实现 LangGraph 工作流,从定义条件边缘函数开始。
def guardrails_condition(
state: OverallState,
) -> Literal["generate_cypher", "generate_final_answer"]:
if state.get("next_action") == "end":
return "generate_final_answer"
elif state.get("next_action") == "movie":
return "generate_cypher"
def validate_cypher_condition(
state: OverallState,
) -> Literal["generate_final_answer", "correct_cypher", "execute_cypher"]:
if state.get("next_action") == "end":
return "generate_final_answer"
elif state.get("next_action") == "correct_cypher":
return "correct_cypher"
elif state.get("next_action") == "execute_cypher":
return "execute_cypher"
现在我们把所有内容整合起来。
from IPython.display import Image, display
from langgraph.graph import END, START, StateGraph
langgraph = StateGraph(OverallState, input=InputState, output=OutputState)
langgraph.add_node(guardrails)
langgraph.add_node(generate_cypher)
langgraph.add_node(validate_cypher)
langgraph.add_node(correct_cypher)
langgraph.add_node(execute_cypher)
langgraph.add_node(generate_final_answer)
langgraph.add_edge(START, "guardrails")
langgraph.add_conditional_edges(
"guardrails",
guardrails_condition,
)
langgraph.add_edge("generate_cypher", "validate_cypher")
langgraph.add_conditional_edges(
"validate_cypher",
validate_cypher_condition,
)
langgraph.add_edge("execute_cypher", "generate_final_answer")
langgraph.add_edge("correct_cypher", "validate_cypher")
langgraph.add_edge("generate_final_answer", END)
langgraph = langgraph.compile()
# View
display(Image(langgraph.get_graph().draw_mermaid_png()))
我们现在可以通过提出一个不相关的问题来测试应用程序。
langgraph.invoke({"question": "What's the weather in Spain?"})
{'answer': "I'm sorry, but I cannot provide current weather information. Please check a reliable weather website or app for the latest updates on the weather in Spain.",
'steps': ['guardrail', 'generate_final_answer']}
现在让我们问一些与电影相关的问题。
langgraph.invoke({"question": "What was the cast of the Casino?"})
{'answer': 'The cast of "Casino" includes Robert De Niro, Joe Pesci, Sharon Stone, and James Woods.',
'steps': ['guardrail',
'generate_cypher',
'validate_cypher',
'execute_cypher',
'generate_final_answer'],
'cypher_statement': "MATCH (m:Movie {title: 'Casino'})<-[:ACTED_IN]-(a:Person) RETURN a.name"}
下一步
有关其他图技术及更多内容,请查看: